The equation in the slope intercept form is obtained as follows:

Given the two points are

A = (8 , 2) On comparing this with (x1, y1) we get that x1 = 8 and y1 = 2

B = (3 , 1) On comparing this with (x2 , y2) we get that x2 = 3 and y2 = 1

Formula: y - y1 = (y2 - y1)/(x2 - x1) * (x - x1)

y - 2 = (1 - 2)/(3 - 8) * (x - 8)

y - 2 = (-1)/(-5) * (x - 8)

y - 2 = 1/5 * (x - 8)

5(y - 2) = (x - 8)

5y - 10 = x - 8

5y = x - 8+ 10

5y = x + 2

y = (x + 2)/5

y = x/5 + 2/5

Therefore the equation of the line in slope intercept form is y = x/5 + 2/5.

Given the two points are

A = (8 , 2) On comparing this with (x1, y1) we get that x1 = 8 and y1 = 2

B = (3 , 1) On comparing this with (x2 , y2) we get that x2 = 3 and y2 = 1

slope = (y2 - y1)/(x2 - x1)

= (1 - 2)/(3 - 8)

= -1/-5 ( the negative signs will be cancelled

therefore slope =1/5

Thanks for your question

Slope of line with two points (8, 2) and (3, 1) can be given as:

m = (y2 - y1) / (x2 - x1)

Therefore : m = (1 - 2) / (3 - 8)

m = (-1) / (-5)

Which gives Slope = m = 1/5

Slope is 2-1 divided by 8-3

= 1/5

y = x/5 + c, need to find c

substituting the point (3, 1) give c = 2/5

so equation of the line is

y = x/5 + 2/5