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How do you evaluate 3x + 5y when x = 11 and y =4

10 Answers
How do you evaluate 3x + 5y when x = 11 and y =4
P

First, plug in the numbers where the variables are, so you get this:
3(11) + 5 (4)

Then, mulitply the 3 and 11. so you have this:
33+5 (4)

Next, multiply the 5 and 4. So you have this:
33+20
Finally, add the numbers to get 53. That is the answer.

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T

- replace the 3 times X with 3 times 11
- replace the 5 times Y with 5 times 4
- then once you have those two answers you add them up
- finally you have your answer

3 x (X) + 5 x( Y) =

3 x 11 + 5 x 4 =
33 + 20 =53

ans: 33

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S

This can be done by calculating the given values in the given equation. This is done as follows,
Given equation, 3x+5y
On Substituting the given values x=11,y=4 in the given equation
3(11)+5(4)=>33+20=>53.
Hence, the obtained result is 53.

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A

Plug in the values of x and y in the equation given:
= 3x + 5y
= 3(11) + 5(4)
= 33 + 20
= 53

Therefore the value of 3x + 5y is 53 when x = 11 and y = 4.

Thank you for the question.

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S

You simply substitute the given value x=11 and y=4
so the equation will be 3(11)+5(4)=n

then simplify, 3(11) is 33 and 5(4) is 20,
33+20 is equal to 53
that's it!

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B

Its really quite simple with the given equation 3x+5y, plug in the given integer values of x and y and there isyour answer

3(11)+5(4)=53

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T

Its really quite simple with the given equation 3x+5y, plug in the given integer values of x and y and there isyour answer

3(11)+5(4)=53

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I

Is this some sort of joke? My dog figured this one out:
kjhfdskjhdfuyvcm,bvuhiubsdmcyui fofncnf=53
Thanks pup!

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C

Just plug in 11 for x and 4 for y
3(11) + 5(4)
33+20= 53



hope this helps

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M

3x + 5y = 3 x 11 + 5 x 4 = 33 + 20 = 53

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